21x^2-40xy+11y^2=

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Solution for 21x^2-40xy+11y^2= equation:


Simplifying
21x2 + -40xy + 11y2 = 0

Reorder the terms:
-40xy + 21x2 + 11y2 = 0

Solving
-40xy + 21x2 + 11y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(7x + -11y)(3x + -1y) = 0

Subproblem 1

Set the factor '(7x + -11y)' equal to zero and attempt to solve: Simplifying 7x + -11y = 0 Solving 7x + -11y = 0 Move all terms containing x to the left, all other terms to the right. Add '11y' to each side of the equation. 7x + -11y + 11y = 0 + 11y Combine like terms: -11y + 11y = 0 7x + 0 = 0 + 11y 7x = 0 + 11y Remove the zero: 7x = 11y Divide each side by '7'. x = 1.571428571y Simplifying x = 1.571428571y

Subproblem 2

Set the factor '(3x + -1y)' equal to zero and attempt to solve: Simplifying 3x + -1y = 0 Solving 3x + -1y = 0 Move all terms containing x to the left, all other terms to the right. Add 'y' to each side of the equation. 3x + -1y + y = 0 + y Combine like terms: -1y + y = 0 3x + 0 = 0 + y 3x = 0 + y Remove the zero: 3x = y Divide each side by '3'. x = 0.3333333333y Simplifying x = 0.3333333333y

Solution

x = {1.571428571y, 0.3333333333y}

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